Retrieving Listbox Information [SOLVED]

  • On 10/12/2014 at 17:44, xxxxxxxx wrote:

    The documentation for how to .GetLink () is confusing. It says I need an instance of a LinkboxUI.

    I don't know how to retrieve what's contained in the linkbox. Would I need to create the LinkBoxUI instance? If so, how exactly do you do that?

    Simple code setup for the UI. Linkbox and a button. Press the button, print what's in the linkbox (well, that's the goal).

    import c4d
    from c4d import gui
    class guiDialog ( gui.GeDialog ) :
        lb = 1000
        btn = 1001
        def CreateLayout ( self ) :
            self.AddCustomGui (, pluginid = c4d.CUSTOMGUI_LINKBOX, name = "Target Object", flags = c4d.BFH_SCALEFIT, minw = 466, minh = 15 )
            self.AddButton ( self.btn, c4d.BFH_SCALEFIT, 120, 15, 'Okay' )
            return True
        def Command ( self, id, msg ) :
            if id == self.btn:
                print 'object name'
            return True
    def main() :
        dialog = guiDialog ()
        dialog.Open ( dlgtype = c4d.DLG_TYPE_MODAL )
    if __name__=='__main__':

  • On 11/12/2014 at 01:52, xxxxxxxx wrote:


    to get the link of a linkbox simply call the GetLink() function of your linkbox. AddCustomGui() will return this linkbox. Either store the returned object or get it using FindCustomGui().

             linkbox = self.FindCustomGui(id=4000,pluginid = c4d.CUSTOMGUI_LINKBOX)  
              if linkbox is not None:  
                  linkedObject = linkbox.GetLink(documents.GetActiveDocument())  
                  if linkedObject is not None:  
                      print linkedObject  

    Best wishes,

  • On 11/12/2014 at 10:14, xxxxxxxx wrote:

    Ah, FindCustomGui(). That's what I was looking for!

    Thank you!

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