Retrieving Listbox Information [SOLVED]

On 10/12/2014 at 17:44, xxxxxxxx wrote:

The documentation for how to .GetLink () is confusing. It says I need an instance of a LinkboxUI.

I don't know how to retrieve what's contained in the linkbox. Would I need to create the LinkBoxUI instance? If so, how exactly do you do that?

Simple code setup for the UI. Linkbox and a button. Press the button, print what's in the linkbox (well, that's the goal).

import c4d
from c4d import gui
class guiDialog ( gui.GeDialog ) :
    lb = 1000
    btn = 1001
    def CreateLayout ( self ) :
        self.AddCustomGui (, pluginid = c4d.CUSTOMGUI_LINKBOX, name = "Target Object", flags = c4d.BFH_SCALEFIT, minw = 466, minh = 15 )
        self.AddButton ( self.btn, c4d.BFH_SCALEFIT, 120, 15, 'Okay' )
        return True
    def Command ( self, id, msg ) :
        if id == self.btn:
            print 'object name'
        return True
def main() :
    dialog = guiDialog ()
    dialog.Open ( dlgtype = c4d.DLG_TYPE_MODAL )
if __name__=='__main__':

On 11/12/2014 at 01:52, xxxxxxxx wrote:


to get the link of a linkbox simply call the GetLink() function of your linkbox. AddCustomGui() will return this linkbox. Either store the returned object or get it using FindCustomGui().

         linkbox = self.FindCustomGui(id=4000,pluginid = c4d.CUSTOMGUI_LINKBOX)  
          if linkbox is not None:  
              linkedObject = linkbox.GetLink(documents.GetActiveDocument())  
              if linkedObject is not None:  
                  print linkedObject  

Best wishes,

On 11/12/2014 at 10:14, xxxxxxxx wrote:

Ah, FindCustomGui(). That's what I was looking for!

Thank you!