Create Xref with python

  • On 18/10/2014 at 11:53, xxxxxxxx wrote:

    I've found a couple posts about this but no clear answers.

    Is it possible to create an Xref object and pass in a file path using python rather than just opening the dialog to search for it? If so, does someone have a code snippet they can share?

    I've got this going so far, but the filepath isn't updating. I guess maybe I need to load a file into the Xref object?

    import c4d   
    def main() :   
        op = c4d.BaseObject(c4d.Oxref)   
        rocket = "/component1.c4d"   
        op[c4d.ID_CA_XREF_FILE_SELECT] = "component1.c4d"   
        op[c4d.ID_CA_XREF_NAMESPACE] = "rocket"   
        op[c4d.ID_CA_XREF_GENERATOR] = 1   
        box = c4d.BaseObject(c4d.Ocube)   

  • On 20/10/2014 at 00:59, xxxxxxxx wrote:


    Due to some limitations it is currently not possible to set the filename parameter of a Xref object in Python.

    Best wishes,

  • On 21/10/2014 at 08:43, xxxxxxxx wrote:

    Any idea of when this will be fixed?

  • On 21/10/2014 at 09:59, xxxxxxxx wrote:

    Sorry, I don't know when this will be fixed.

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