On 05/09/2014 at 14:09, xxxxxxxx wrote:
User Information:
Cinema 4D Version: 14
Platform: Windows ;
Language(s) : C++ ;
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I have, in my code, variables of type String and variables of type string.
I'm using some std:: stuff so I must use string instead of String.
It compiles and works fine on my Mac.
But while trying to compile it in Windows, I get lots of errors and the compilation fails.
Is there anything that can be done?
On 05/09/2014 at 16:49, xxxxxxxx wrote:
Why does it compile without a single complain in Xcode and, in Visual Studio I get dozens of errors?!?
On 05/09/2014 at 18:39, xxxxxxxx wrote:
Are you making string explicit to the std library by using std::string for references?
On 05/09/2014 at 18:52, xxxxxxxx wrote:
std is a namespace. You can declare the namespace for referencing objects in that space explicitly (std::space) or implicitly (using namespace std) somewhere at the top of the file. Which to use will depend on if there are possible clashes. Let's say you have a string type in std and another in another namespace included in your code. If they are not explicitly declared, there is a chance that the compiler doesn't understand which one to use. If you are just using 'string', you must add 'using namespace std'.
On 06/09/2014 at 14:54, xxxxxxxx wrote:
Thank you so much, Robert.
What was happening was the I had these two lines:
template <typename T> string tostr(const T& t) { ostringstream os; os<<t; return os.str(); }
using namespace std;
and I simply had to switch them, like this:
using namespace std;
template <typename T> string tostr(const T& t) { ostringstream os; os<<t; return os.str(); }
The correct way is the second, of course. But it is weird that Xcode doesn't complain and makes it work, somehow.
On 06/09/2014 at 15:59, xxxxxxxx wrote:
Technically, you can declare 'using namespace' anywhere in the global scope of the source code. You can do this with '#include" for headers as well. It is generally safer to do these first nonetheless. And you want to declare the namespace after any header that defines it (!).
