get face number count for geometrics

Helper

THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED

On 26/10/2007 at 02:08, xxxxxxxx wrote:

User Information:
Cinema 4D Version:   9.5
Platform:   Windows ;
Language(s) :     C++ ;

---------
I want to find out and get the face number of count result and vertex number .... but I have a little trouble that my code can't get back the correct result :

my code:

void GetAllPolygon(AtomArray *oPolygons,BaseObject *oPolys)
{
     if(oPolys)
     {

   //MessageDialog("GetType Begin");
   if( oPolys->GetType() == Opolygonn ) //||( oPolys->GetType() == Ocylinder)||( oPolys->GetType() == Ocube)||( oPolys->GetType() == Osphere))
   {
    oPolygons->Append(oPolys);
   }

         if(oPolys->GetDown())
   {
    GetAllPolygon(oPolygons,oPolys->GetDown());
   }

   if(oPolys->GetNext())
   {
    GetAllPolygon(oPolygons,oPolys->GetNext());
   }

   }
  // MessageDialog("GetNext End");

}
LONG GetAllPolygon(AtomArray * oPolygon)
{
     if(!oPolygon)
{
   //MessageDialog("Alloc AtomArray Fail that Can't get polygon ");
   return 0;
}
     BaseDocument *doc=GetActiveDocument();
     BaseObject *obj = doc->GetFirstObject();
     if(obj)
     {
    //MessageDialog("To get polyon ");
          GetAllPolygon(oPolygon,obj);
     }
     return oPolygon->GetCount();
}

void SnapPolygonData( AtomArray *oPolygons, LONG lPolygonCnt, LONG& out_iFaceNumCount, LONG& out_iVertexNumCount)
{
LONG nCount = 0;
if ( lPolygonCnt == 0)
{
  return;
}
BaseDocument* doc = GetActiveDocument();
//MessageDialog( LongToString(lPolygonCnt) );
    for(LONG i = 0;i < lPolygonCnt; i++)
    {
        PolygonObject *obj=(PolygonObject* )oPolygons->GetIndex(i);
        //MessageDialog(obj->GetName());
  if ( !obj) break;

  LONG lngFace = obj->GetPolygonCount();
  LONG lngVertex = obj->GetNgonCount();
  out_iFaceNumCount += lngFace;
  out_iVertexNumCount += lngVertex;

    }

}
bool GetMetaData( LONG& out_iFaceCount, LONG& out_iVertexCount )
{
  LONG iFaceNumCount = 0;
LONG iVertexNumCount = 0;
AtomArray* oPolygons = AtomArray::Alloc();
if ( !oPolygons )
{
  MessageDialog( "AtomArray Alloc Is Fail" );
  return false;
}
//MessageDialog( "AtomArray Alloc Is Succuss" );

    LONG lPolygonCnt = GetAllPolygon(oPolygons);
MessageDialog( LongToString(lPolygonCnt) );
SnapPolygonData( oPolygons, lPolygonCnt, iFaceNumCount, iVertexNumCount);

out_iFaceCount = iFaceNumCount;
out_iVertexCount = iVertexNumCount;

AtomArray::Free(oPolygons) ;

return true;
}

Helper

THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED

On 26/10/2007 at 05:10, xxxxxxxx wrote:

where in your code do you run into problems?

cheers,
Matthias

Helper

THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED

On 28/10/2007 at 17:58, xxxxxxxx wrote:

that can't to get polygon object and count face number back when I had added cube to scence after. show me the result of polygon's face and vertex number is 0;

Helper

THE POST BELOW IS MORE THAN 5 YEARS OLD. RELATED SUPPORT INFORMATION MIGHT BE OUTDATED OR DEPRECATED

On 02/11/2007 at 04:49, xxxxxxxx wrote:

It seems you don't convert your primitve objects into polygon objects. For instance you have first to convert the cube into a polygon object to access the polygons. The savest way to it is by using SendModelingCommand() to get the current state of your object. Here a little example.

> _
> Bool MenuTest::Execute(BaseDocument *doc)
> {
>      StopAllThreads();
>
>      BaseObject *op = doc->GetActiveObject();
>      if(!op) return TRUE;
>
>      BaseObject *res = NULL;
>      ModelingCommandData cd;
>      cd.doc = doc;
>      cd.op = op;
>      if(!SendModelingCommand(MCOMMAND_CURRENTSTATETOOBJECT, cd)) return FALSE;
>      res = static_cast<BaseObject*>(cd.result->GetIndex(0));
>
>      if(!res) return FALSE;
>
>      if(res->GetType() == Opolygon)
>      {
>           GePrint("point count "+LongToString(ToPoly(res)->GetPointCount()));
>      }
>
>      return TRUE;
> }
> _

cheers,
Matthias