I'm writing a script that exports the position of an object. In the process, I'm truncating them to only four decimals.

Wrote the a truncate function. It works but not on low numbers.

For example,

```
Actual Position: Vector(0, 139.213, 93.26)
X-Position: 2.42398958609e-05
Resulting truncation: 2.4239
```

It turns out the script reads the `pseudo decimal`

to an actual decimal. Is there a way to read the numbers as this `0.0000242398958609`

so the function works as expected or should I revise the function?

Here is the current code:

```
def truncate(num):
num_str = str(num)
num = num_str.split(".")
num_real = num[0]
num_dec = num[1][:4]
new_num_str = "{}.{}".format(num_real, num_dec)
new_num = float(new_num_str)
return new_num
```

]]>Thanks again @zipit for the fast and nice reply

I also move this thread to general programming as it's not related to Cinema 4D

Cheers,

Manuel

THanks for the reminder. I initially thought I could get away with such a rudimetary approach

RE: code

Interesting. Your algorithm is way more useful. Thanks for sharing.

that your script is not working has not anything to do with `pseudo decimals`

, but the fact that you are treating numbers as strings (which is generally a bad idea) in a not very careful manner. When you truncate the string representation of a number which is represented in scientific notation (with an exponent), then you also truncate that exponent and therefor change the value of the number.

To truncate a `float`

you can either take the `floor`

of `my_float * 10 ** digits`

and then divide by `10 ** digits`

again or use the keyword `round`

.

```
data = [0.03659665587738824,
0.00018878623163019122,
1.1076812650509394e-03,
1.3882258325566638e-06]
for n in data:
rounded = round(n, 4)
floored = int(n * 10000) / 10000
print(n, rounded, floored)
0.03659665587738824 0.0366 0.0365
0.00018878623163019122 0.0002 0.0001
0.0011076812650509394 0.0011 0.0011
1.3882258325566637e-06 0.0 0.0
[Finished in 0.1s]
```

Cheers

zipit